Needs For Aptitude Test :
Aptitude tests are
usually administered online – most often after a candidate has made
their initial job application – and are used to filter unsuitable
applicants out of the selection process, without the need for
time-consuming one-to-one job interviews.
1. Today it is Thursday.After 132 days,it will be
(d) Thursday
Answer: Wednesday
Explanation:
Since each day of the week is repeated after 7 days.
After 133 days,it will be thursday.
So one day before that would be Wednesday.
2. A train 120 meters long is running with a
speed of 60 km/hr. In what time will it pass a boy who is running at 6
km/hr in the direction opposite to that in which the train is going?
Answer: 6.54 sec
Explanation:
Speed of train relative to boy= `(60 + 6)` km/hr = 66 km/hr
`= [66 xx 5/18]` m/sec = `[55/3]` m/sec.
Time taken to pass the boy=` [120 xx 3/55]` sec = 6.54 seconds
3. Danny can cover a certain distance in 1 hour 24 minutes by covering two-third
of the distance at 6 km/hour and the rest at 7 km/hr. Calculate total
distance.
(d) 7/5 km
Answer: 6 km
Explanation: Let the total distance be x , then
[{(2/3) x }/6 ] + [{(1/3) x }/7 ] = 7/5`
=> x/9 + x/21 = 7/5`
=> 7x = 63`
=> x = 9`
Therefore , total distance = `6 km`
4. Find the H.C.F, if the numbers are in the ratio of 4 : 5 : 6 and their L.C.M. is 2400.
(d) 67
Answer: 20
Explanation: Let the numbers be 3x, 4x and 5x.
Then,their L.C.M. = 120x.
So, 120x = 2400 or x = 20.
=>The numbers are (4 x 20), (5 x 20) and (6 x 20).
Hence, required H.C.F = 20.
5. What is the value of c , If 8 is 4% of a, and 4 is 8% of b. c equals b/a.
Answer: 1/4
Explanation:
Let be the 4% of a is 4a/100.
Since this equals 8, we have 4a/100=8.
Solving for a yields a=8×`(100/4)`=200.
Also, 8% of b equals 8b/100, and this equals 4.
Hence, we have `(8/100)`×b=4.
Solving for b yields b = 50.
Now, c=`b/a`=`50/200`=`1/4.`
6. P and Q take part in 100 m race. P runs at 6kmph. P gives Q a start of 8 m and still beats him by 8 seconds. The speed of Q is:
(d) 4.86 kmph
Answer: 4.86 kmph
Explanation:
speed =( 6**5/18)m/sec) = (30/18) m/sec
Time taken by P to cover 100 m = `(100 ** 18/30)`m/sec =60 sec
Time taken by Q to cover 92 m = (60 + 8) = 68 sec.
Q's speed =`("Distance"/"Time"**18/5) kmph =(92/68 ** 18/5)` kmph = 4.86kmph.
7. Find
the speed of the boat in still water, if a boat covers a
certain distance upstream in 2 hours, while it comes back in 1`1/2`
hours. If the speed of the stream be 3 kmph.
(d) 24 Kmph
Answer: 21 Kmph
Explanation: Let the speed of the boat in still water be x kmph. Then,
Speed downstream = (x + 3) kmph,
Speed upstream = (x - 3)kmph.
`(x - 3) * 2 = (x + 3) * 3/2`
4x - 12 = 3x + 9
x = 21kmph.
8. In
covering a distance of 40 km, Kamlesh takes 2 hours more than Pankaj.
If Kamlesh doubles his speed, then he would take 1 hour less than
Pankaj. Then what is Kamlesh's speed?
Answer: 5 Kmph
Explanation:
Let Kamlesh’s speed be x km/hr.
Then, `40/x - 40/(2x) = 4`
8x = 40
x = 5 km/hr
No comments:
Post a Comment