Frequently asked aptitude question for interviews

 

Needs For Aptitude Test :

 Aptitude tests are usually administered online – most often after a candidate has made their initial job application – and are used to filter unsuitable applicants out of the selection process, without the need for time-consuming one-to-one job interviews.

1. Today it is Thursday.After 132 days,it will be

 

(a) Monday

(b) Sunday

(c) Wednesday

(d) Thursday

 

Answer: Wednesday

 

Explanation:

Since each day of the week is repeated after 7 days.

After 133 days,it will be thursday.

So one day before that would be Wednesday.

 

2. A train 120 meters long is running with a speed of 60 km/hr. In what time will it pass a boy who is running at 6 km/hr in the direction opposite to that in which the train is going?

(a) 6.54 sec

(b) 44.32 sec

(c) 55 sec

(d) 30.2 sec

 

Answer: 6.54 sec

Explanation:

Speed of train relative to boy= `(60 + 6)` km/hr = 66 km/hr

`= [66 xx 5/18]` m/sec = `[55/3]` m/sec.

Time taken to pass the boy=` [120 xx 3/55]` sec = 6.54 seconds

3. Danny can cover a certain distance in 1 hour 24 minutes by covering two-third of the distance at 6     km/hour and the rest at 7 km/hr. Calculate total distance.

 

(a) 8 km

(b) 9 km

(c) 6 km

(d) 7/5 km

 

Answer: 6 km

 

Explanation: 

 Let the total distance be x , then

[{(2/3) x }/6 ] + [{(1/3) x }/7 ] = 7/5`

=>   x/9 + x/21 = 7/5`

=>   7x = 63`

=>   x = 9`

 Therefore , total distance = `6 km`

 

 

4. Find the H.C.F, if the numbers are in the ratio of 4 : 5 : 6 and their L.C.M. is 2400.

 

(a) 35

(b) 20

(c) 40

(d) 67

 

Answer: 20

 

Explanation: 

Let the numbers be 3x, 4x and 5x.

Then,their L.C.M. = 120x.

So, 120x = 2400 or x = 20.

=>The numbers are (4 x 20), (5 x 20) and (6 x 20).

Hence, required H.C.F = 20.

 

5. What is the value of c , If 8 is 4% of a, and 4 is 8% of b. c equals b/a.

 

(a) 12

(b) 1/4

(c) 0.155

(d) None of these

 Answer: 1/4

Explanation:

Let be the 4% of a is 4a/100.

Since this equals 8, we have 4a/100=8.

Solving for a yields a=8×`(100/4)`=200.

Also, 8% of b equals 8b/100, and this equals 4. 

Hence, we have `(8/100)`×b=4. 

Solving for b yields  b = 50.

Now, c=`b/a`=`50/200`=`1/4.`

 

6. P and Q take part in 100 m race. P runs at 6kmph. P gives Q a start of 8 m and still beats him by 8 seconds. The speed of Q is:

 

(a) 6.14 kmph

(b) 15.2 kmph

(c) 5 kmph

(d) 4.86 kmph

 

Answer: 4.86 kmph

 

Explanation:

 

 speed =( 6**5/18)m/sec) = (30/18) m/sec

Time taken by P to cover 100 m = `(100 ** 18/30)`m/sec =60 sec

Time taken by Q to cover 92 m = (60 + 8) = 68 sec.

Q's speed =`("Distance"/"Time"**18/5) kmph =(92/68 ** 18/5)` kmph = 4.86kmph.

 

 

7. Find the speed of the boat in still water, if a boat covers a certain distance upstream in 2 hours, while it comes back in 1`1/2` hours. If the speed of the stream be 3 kmph.

 

(a) 12 Kmph

(b) 18 Kmph

(c) 21 Kmph

(d) 24 Kmph

 

Answer: 21 Kmph

 

Explanation: 

Let the speed of the boat in still water be x kmph. Then,

Speed downstream = (x + 3) kmph,

Speed upstream = (x - 3)kmph.

`(x - 3) * 2 = (x + 3) * 3/2`

4x - 12 = 3x + 9

x = 21kmph.

 

8. In covering a distance of 40 km, Kamlesh takes 2 hours more than Pankaj. If Kamlesh doubles his speed, then he would take 1 hour less than Pankaj. Then what is Kamlesh's speed?

(a) 11 Kmph

(b) 5 Kmph

(c) 9 Kmph

(d) 6 Kmph

Answer: 5 Kmph

Explanation:

Let Kamlesh’s speed be x km/hr.

Then, `40/x - 40/(2x) = 4`

8x = 40

x = 5 km/hr